what is the 20th term of the following arithmetic sequence?
\[\frac{ 1 }{ 2 }, 1, \frac{ 3 }{ 2 }, 2\]
@zepdrix
\[\Large a_1=\frac{1}{2}, \qquad a_2=1\] If we subtract,\[\Large a_2-a_1=1-\frac{1}{2}\]Let's call this value k.\[\Large k=\frac{1}{2}\] This is the common difference between each term.
The nth term is given by,\[\Large a_n=a_1+(n-1)k\]
\[\Large a_{20}=?\]Can you figure this one out? :) Plug in 20 for all of your n's. And plug in the first value for a_1.
a20 = 30?
Hmm let's fill in the pieces.\[\Large a_\color{royalblue}{n}=\color{orangered}{a_1}+(\color{royalblue}{n}-1)\color{green}{k}\] \[\Large \color{royalblue}{n=20},\qquad\qquad \color{orangered}{a_1=\frac{1}{2}},\qquad\qquad \color{green}{k=\frac{1}{2}}\]
\[\Large a_\color{royalblue}{20}=\color{orangered}{\frac{1}{2}}+(\color{royalblue}{20}-1)\color{green}{\frac{1}{2}}\]
Try to solve that! :D
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