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Calculus1 7 Online
OpenStudy (anonymous):

Please help me evaluate the following limit: Kindly find attached

OpenStudy (anonymous):

OpenStudy (anonymous):

Please don't use L’Hˆopital’s Rule. Kindly use another approach. Thanks!

Directrix (directrix):

Any particular reason that L'Hospital's Rule cannot be used? @fireofsky

OpenStudy (anonymous):

No. It is just I want to know the way without using L’Hˆopital’s Rule. Otherwise it'll be very easy. Right?

OpenStudy (anonymous):

Do you know derivatives?

OpenStudy (anonymous):

Yes. I know

OpenStudy (anonymous):

This is f'(0) for a certain f(x). Which f(x) and why?

hartnn (hartnn):

just plug in x=y^3-1 sowhat will be numerator ?

hartnn (hartnn):

also note that when x->0, y->1

OpenStudy (anonymous):

I see. thank you so much.!!!

OpenStudy (anonymous):

\[ f(x)=\sqrt[3]{x+1}\\ \]

OpenStudy (anonymous):

\[ f'(x)=\frac{1}{3 (x+1)^{2/3}}\\ f'(0)=\frac 1 3 \]

OpenStudy (anonymous):

can u show more details please?

OpenStudy (anonymous):

okay. but why? not using L'Hospital's Rule

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