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solve dy/dx=xy/x^2+3y^2
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\[\frac{dy}{dx} = \frac{xy}{x^2+3y^2}\] i think this is possible by \( u =y/x)
\( u = y/x\)
okay cool...thnx...dis is what i wanted 2 know:)
thats all lol?
mimi to the rescue!
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hehe ;)
yep...i just wanted 2 confirm if i m proceeding in d right direction...
!@Mimi_x3 could u plz check if this ans is correct? logx+x^2/6y^2+log(y/x)=c
@Mimi_x3
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i got something retarded though :P
Ok ill check...thnx:)
Do des answers match by sum changes??:p
@hartnn @mimi
dont forget the constant of integration
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ye lol, woops
\[x^2+3y^2=3xy\ln x+Axy\]
ok thnx...:)@UnkleRhaukus
thnx a ton:)
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Thnx 2 all @Mimi_x3 @hartnn @UnkleRhaukus
ive got a minus sign error in my working
ohhh..i need 2 check again den
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