Question

Exponents and logarithms and radical numbers...sooo simplify the expression

Answer 1

\[\sqrt{12}\]

Answer 2

The answer is \[2\sqrt{3}\] and you plz write how and why

Answer 3

12 = 4 . 3
Right ?

Answer 4

4=2^2
and we can answer this in radical 2 but dont have any answer for 3 so have :
\[\sqrt{12}=\sqrt{4*3}=\sqrt{2^2*3}=\sqrt{3}*2\]
Got it ?:)

Answer 5

@ojeano

Answer 6

Factorization and reduction: \[\sqrt{12} => \sqrt{4*3}=>\sqrt{4}*\sqrt{3} => 2\sqrt{3}\]
Alternate using exponentials: \[\sqrt{12 } => (12)^{1/2} => (4*3)^{1/2} => (4)^{1/2} * (3)^{1/2} => (2^{2})^{1/2}*(3)^{1/2} => 2(3)^{1/2} =>2\sqrt{3)}\]

Answer 7

@kjburketx
: Thank u !

Answer 8

Realy right and clear :)

Answer 9

@ojeano :Got it ????:)

Answer 10

I should have included these identities: 1) \[\sqrt{x} = x ^{1/2}\] , in general,
\[\sqrt[a]{x} = x^{1/a}\]
and 2) \[(x ^{a})^{b} = x ^{a*b},
so, (x ^{1/2})^{2} = x ^{1/2 * 2} = x ^{1} = x \]

(Sorry... noobie getting used to the equation writer) :-)

Answer 11

omg yes thank you very much both of you @kjburktex and @E.ali