Question

Solve the equation:

Answer 1

Where is it? Did some birdie eat it?

Answer 2

\[\frac{ 3 }{ x-3 }=6+\frac{ x }{ x-3}\]

Answer 3

I think it's no solution, but that's just because I can't think of a way to start this.

Answer 4

@CGGURUMANJUNATH could you please help me?

Answer 5

\[\frac{ 3 }{ x-3 }=6+\frac{ x }{ x-3}\]

Subtract \(\dfrac{3}{x-3}\) from both sides to get:
\[0=6+\frac{ x }{ x-3} - \frac{ 3 }{ x-3 }\]

Combine fractions to get:
\[0=6+\frac{ x -3 }{ x-3}\]

\(\dfrac{ x -3 }{ x-3} = 1\) so..

\[0=6+1\]
\[0 = 7\]False

Answer 6

Thus no solution

Answer 7

Any thoughts @rrey ?

Answer 8

No, I understand.

Answer 9

Wait, so is this equation an identity?

Answer 10

no wait it's a contradiction right?

Answer 11

Exactly

Answer 12

multiply each term by (x-3), and you should get, 3 = 6(x-3) + x