diethyl ether is produced from ethanol according to the following equation
2CH3CH2OH---CH3CH2OCH2CH3+H2O
What mass of ether will be produced if 217 g of ethanol reacts with a 79.3 percent yield??

Question

diethyl ether is produced from ethanol according to the following equation 
2CH3CH2OH--->CH3CH2OCH2CH3+H2O
What mass of ether will be produced if 217 g of ethanol reacts with a 79.3 percent yield??

anonymous · Answer

perhaps 174.54 grams

anonymous · Answer

or 276.84   im not confident but thats a hard question

anonymous · Answer

how did you get that?

anonymous · Answer

Percentage Yield =     mass of Actual Yield/mass of Theoretical Yield    x 100%
You would first need to calculate moles of ethanol, n=217/MM then use the ratios in the balance equations which means you divide the moles by 2 to get moles produced for the ether. Now you would need to multiply that by the molar mass of the ether inorder ot get the theoretical mass produced. Then use the equation and solve for mass of actual yield