Question

Calculate the initial speed, v0, of a long-jumper where d=7.56 m. Assume a take-off angle of 22.5°, an initial height of the centre-of-mass of 0.920 m, and a final height of 0.460 m.

Answer 1

in the x or y direction or the magnitude of v0

Answer 2

Looking for the magnitude of v

Answer 3

What is the centre-of-mass?

Answer 4

Idk I am sorry

Answer 5

Oh it's the distance from the ground to the middle of the jumper's body per say. The value is 0.920m. I'm assuming its just a beginning height

Answer 6

Check the attachment for a visual of the problem :)

Answer 7

I did I am working on it idk if it is right though

Answer 8

I wish u had time

Answer 9

I'm sure we can find t

Answer 10

t0 = 0

Answer 11

-.46+(4.9)(57.1536/Vocos^2(22.5))= (.5)(Votan22.5)(7.56)

Answer 12

And seriously ughg

Answer 13

What is t final

Answer 14

That I do not know

Answer 15

this question is quite the nuisance