Question

Could someone help me with this please? ><

Answer 1

"nint" sounds like "nearest integer"

Answer 2

so plug in various values of x to get corresponding values of y

this will give you a series of points to plot

Answer 3

ex: when x = 1.2

y = nint(x)

y = nint(1.2)

y = 1

so the point (1.2, 1) is on the graph

Answer 4

Okay that makes sense...how do I graph that? This is what I have
-1.5 = -2
-1.3 = -2
-1 = 0
-0.8 = 0
-0.5 = 0
-0.3 = 0
0 = 0
where do I go from tehre? or is that all I need?

Answer 5

the nearest integer for -1.3 is -1 not -2

Answer 6

-1 is already an integer, so leave it as it is

Answer 7

-0.8 is closer to -1 than it is to 0

Answer 8

so is -0.5

Answer 9

I thought for nearest integer you have to round it to an even number?

Answer 10

ohh, that's just for decimals

Answer 11

no to the nearest integer (ie whole number)

Answer 12

My book says "To avoid confusion for numbers such as -1.5 and 3.5, the function assigns the nearest even integer to each input value. So nint(-1.5) = -2, while nint(3.5) = 4." This is what has me confused?

Answer 13

yeah because -1.5 is close to -2 (it's right halfway between 0 and -1, but you usually round up)

Answer 14

same for 3.5

it's right between 3 and 4, but you round up

Answer 15

So it should be
-1.5 = -2
-1.3 = -2
-1 = -1
-0.8 = 0
-0.5 = 0
-0.3 = 0
0 = 0
like that?

Answer 16

-0.8 is closer to -1, not 0

same for -0.5

Answer 17

So really its the nearest integer, not nearest even integer?

Answer 18

yes, I'm not sure where you're seeing " nearest even integer" since that makes no sense at all

just go for the closest whole number

Answer 19

Well its what my book says and my teacher taught us that too, its really confusing

Answer 20

hmm maybe you're thinking of a different function?

nint is basically rounding whatever input you plug in to the nearest whole number

Answer 21

It says nearest integer function, I'll type the paragraph

"The nearest integer function, denoted by nint(x), assigns the nearest integer to each real number in an interval. To avoid confusion for numbers such as -1.5 and 3.5, the function assigns the nearest even integer to each input value. So nint(-1.5) = -2, while nint(3.5) = 4. The nearest integer for numbers in the interval [-0.5, 0.5] is zero."

Answer 22

hmm that's so odd

Answer 23

well I guess you better stick to those rules then

Answer 24

basically what it's saying is if you're at some number that has ".5" in it, then pick the number that's even

eg:

nint(0.5) = 0 (we could pick either 0 or 1, but the rules tell us to pick an even number)

nint(1.5) = 2

nint(2.5) = 2

nint(3.5) = 4

nint(4.5) = 4

etc etc

Answer 25

So with the problem I have do I have to do that for every single number from -1.5 to 1.5?

Answer 26

no just numbers that have 5 right after the decimal point

numbers like: 0.5, 1.5, 2.5, 3.5, 4.5, etc

Answer 27

why these numbers? because they are exactly at the midpoint of each consecutive integer pair

Answer 28

you round like normal for every other input

Answer 29

Okay so
-1.5 = -2
-1 = -1
-0.5 = 0
0 = 0
and then
1.5 = 2
1 = 1
0.5 = 0
0 = 0

Answer 30

good

Answer 31

so that gives you a bunch of points to plot

Answer 32

keep in mind that this isn't a continuous graph

Answer 33

it will look like a staircase (that isn't connected)

Answer 34

Okay, I'll try to graph it

Answer 35

Is that right so far?

Answer 36

yes, so far, so good

Answer 37

I know that the highest dot I made is as highest I can go, but I'm not sure what to point between the 0,0 and the highest point

Answer 38

hmm wait, I'm getting this graph with geogebra

Answer 39

I have geogebra, but I don't know how to use it yet ><
I see the graph, but I still don't understand how that is the answer? I know it is, just don't understand it yet

Answer 40

well I graphed a shifted version of the "ceil" function

the "ceil" function basically always rounds up to make sure the outputs are integers

then I added endpoints (closed and open circles) on top of that graph

Answer 41

Oohh, I need to take a tutorial on geogebra, it looks like it will really help with this

Answer 42

yeah it's a very handy graphing program