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OpenStudy (accidentalaichan):
Hm, I seem to be a stick in the mud with this one:
What is the slope of the line that passes through (0,1) and is parallel to y = 5x + 3?
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jimthompson5910 (jim_thompson5910):
The slope of y = 5x + 3 is m = ______ (fill in the blank)
OpenStudy (accidentalaichan):
m=5?
jimthompson5910 (jim_thompson5910):
so the slope of any line parallel to y = 5x + 3 is also 5
this is because if two lines are parallel, then their slopes are equal
jimthompson5910 (jim_thompson5910):
we know that m = 5 (parallel slope) and the given point on this parallel line is (0,1)
so that means that when x = 0, y = 1
jimthompson5910 (jim_thompson5910):
y = mx + b
y = 5x + b ... plug in the parallel slope m = 5
1 = 5(0) + b ... plug in the given point (0,1)
now solve for b and tell me what you get
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OpenStudy (accidentalaichan):
1 = 0 + b
1 = b
jimthompson5910 (jim_thompson5910):
so m = 5, b = 1
jimthompson5910 (jim_thompson5910):
y = mx+b
y = 5x + 1
jimthompson5910 (jim_thompson5910):
that's the equation of the parallel line that goes through (0,1)
OpenStudy (accidentalaichan):
Thanks so much!
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jimthompson5910 (jim_thompson5910):
you're welcome
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