Question

A Ferrari accelerates from 0 to 100.0 km/h in
4 .80 s. What force (in Newtons) does a passenger of mass 96.0 kg experience during acceleration?

I found;

F=ma
=556N ?

Answer 1

100x(100/360)=27.7 (to change km/h to m/s)
27.7/4.8=5.787 (to solve acceleration)
5.787x96=555.5 (to solve force)
therefore your answer is correct.

Answer 2

We know that:
\[F=ma\]
We also know that:
\[m=\frac{\Delta v}{\Delta t}=\frac{v_2-v_1}{t_2-t_1}\]
So we can simplify:
\[F=m\left(\frac{v_2-v_1}{t_2-t_1}\right)\]
So then we have the following:
\[\eqalign{
&m=96.0kg \\
&v_1=0m/s \\
&v_2=100.0km/h=\frac{100.0km}{h}\times\frac{1h}{3600s}\times\frac{1000m}{1km}=(100/36)m/s\approx27.78m/s \\
&t_1=0s \\
&t_2=4.8s \\
}\]
So we can plug everything in:
\[F=m\left(\frac{v_2-v_1}{t_2-t_1}\right)=(96.0)\left(\frac{27.78-0}{4.8-0}\right)=96\times\frac{27.78}{4.8}\approx555.6N\]

Answer 3

Using significant digits though, you would round to 556N

Answer 4

thanks.)

Answer 5

Lol Anytime!