Question

help please..A 18.01 g sample of N2 reacts with 3.02g of H2 to form ammonia(NH3). what mass of ammonia is formed?

Answer 1

I have the balanced equation N2+3H2->2NH3 what should i do next?

Answer 2

u should find limiting reagent for the reaction N2 or H2 ?

Answer 3

how would I find it?

Answer 4

see the balanced equation for one mole of N2 u need 3 mole of H2 right

Answer 5

yes

Answer 6

H2 and N2 molar mass?
convert the gram into moles present the question

Answer 7

okay and if i find the mole of H2 and then multiply it by the ratio?

Answer 8

nope u find it first

Answer 9

okay I got 0.64mole for N2 and 1.50 mole for H2. what do I do next?

Answer 10

good

Answer 11

so according to balanced equation u need
3 mole of H2 for 1 mole of N2
1.50 moles of H2 u need =1.5*1/3 =0.5 moles of N2

Answer 12

but u have 0.64 moles of N2

Answer 13

mean u have excess of N2 than required for ur H2

Answer 14

so H2 is the limiting reagent

Answer 15

okay after I know H2 is the limiting reagent what do I do next?

Answer 16

NH3 molar mass ?

Answer 17

17.04 NH3

Answer 18

sorry here N2 is limiting reagent :P my bad

Answer 19

its okay

Answer 20

14 gramof N@2 give rise to 2*17 gramof ammonia than
18 gramof N2 =2*17*18 /14 =

Answer 21

43.8?

Answer 22

its simple maths i dont wanna say this at east

Answer 23

its simple maths i dont wanna say this at least