Question

Need Help!!
PLEASEE HELP

Answer 1

options are:
a) 5 cubed root of 2 end root minus 2 cubed root of 3

b) 4 cubed root of 2

c) cubed root of 46

d) 4

Answer 2

Can you factor 54, 16, and 24 into prime factors?

Answer 3

i'll try

Answer 4

Do you know how to factor a number into prime factors?

Answer 5

the answer is A 100% sure, your welcome

Answer 6

find out which one of the awnsers i equal to 3.14510609

Answer 7

yea kinda @mathstudent55
prime factors of 54: 2, 3, 3, and 3
prime factor of 16: 2
prime factors: 2 and 3

Answer 8

@samsterz how r u so sure?

Answer 9

im 100% sure, dont worry, no lie, trust me

Answer 10

and if i get it wrong?

Answer 11

no chance

Answer 12

lets say i do then wat?

Answer 13

You need to list all the prime factors for each number:
54 = 2 * 3 * 3 * 3
16 = 2 * 2 * 2 * 2
24 = 2 * 2 * 2 * 3
Ok?

Answer 14

here ill pm u what i did

Answer 15

ok

Answer 16

100% sure, I promise the answers I gave u for this question and the other one

Answer 17

here ill pm u what i did

Answer 18

Just like you simplify a square root by taking out pairs of factors, you simplify a cubic root by taking out three factors.

For a square root:
For example, \( \sqrt{8} = \sqrt{2 \times 2 \times 2} = \sqrt{4 \times 2} = 2\sqrt{2}\)

Answer 19

For a cubic root:
For example, \( \sqrt[3]{16} = \sqrt[3]{2 \times 2 \times 2 \times 2} = \sqrt[3]{8 \times 2} = 2\sqrt[3]{2}\)

Answer 20

Now we use the prime factors for each nuumber in the cubic root:

\( \sqrt[3]{54} + \sqrt[3]{16} - \sqrt[3]{24} \)

\( =\sqrt[3]{2 \times 3^3} + \sqrt[3]{2 \times 2^3} - \sqrt[3]{2^3 \times 3} \)

\( =\sqrt[3]{2} \sqrt[3]{3^3} + \sqrt[3]{2} \sqrt[3]{ 2^3} - \sqrt[3]{2^3} \sqrt[3]{ 3} \)

\( =3\sqrt[3]{2} + 2\sqrt[3]{2} - 2 \sqrt[3]{ 3} \)

\( =5\sqrt[3]{2} - 2 \sqrt[3]{ 3} \)