Question

4x^2+20x=24

Answer 1

Put in the form,
\[ax^2+bx+c=0\Rightarrow 4x^2+20x-24=0\]
Divide by 4 all the equation,
\[x^2+5x-6=0\]
Now you can complete squares or use the equation,
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] In this case,
\[x=\frac{-5\pm\sqrt{25-4\cdot1\cdot(-6)}}{2\cdot1}=\frac{-5\pm7}{2}\]
So your solutions are, x=1 and x=-6.

Answer 2

Once you get to this point,

\(x^2 + 5x - 6 = 0\)

you can also solve by factoring:

\((x + 6)(x - 1) = 0\)

\(x + 6 = 0\) or \(x - 1 = 0\)

\(x = -6\) or \( x = 1\)