Question

diethyl ether is produced from ethanol according to the following equation
2CH3CH2OH--->CH3CH2OCH2CH3+H2O
What mass of ether will be produced if 217 g of ethanol reacts with a 79.3 percent yield??

Answer 1

Hi,
I think u know abt stoichiometry. Even if u don't know about it from the equation given in the question u must be able to get this data.
If there was 2 mole of ethanol ---> there will be 1 mole of ether

This piece of data can get by the balance equation here,
2CH3CH2OH--->CH3CH2OCH2CH3+H2O
'cause here 2 of CH3CH2OH has turned in to 1 of CH3CH2OCH2CH3
which means 2 mole of CH3CH2OH will turn in to 1 mole of CH3CH2OCH2CH3

The ratio between these 2 values is known as the stoichiometric ratio.which is represent by
\[\frac{ \Delta n _{ethanol} }{\Delta n _{either} } = \frac{ 2 }{ 1 } = 2\]

Now before moving to find the value in the given question u must find the theoretical yield
using that ratio.

Here the no. mole of ethanol is 217/46 = 4.717
if 2 mole of ethanol reacts to produce i mole of either
then how many mole of either will formed when 4.717 mole of ethanol reacts ?

can u find that bro...?