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OpenStudy (anonymous):
wait, what? whats the full equation?
OpenStudy (loser66):
you have to have the form of solution are x<-6 or x>2
OpenStudy (anonymous):
x2-4x>12
OpenStudy (anonymous):
x^2-4x>12 u mean?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
sorry having problems with my computer..lol
OpenStudy (anonymous):
never mind
OpenStudy (anonymous):
x<-2 or x>6
OpenStudy (john_es):
I think the solution should be an interval.
OpenStudy (john_es):
An open interval to be more specific.
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OpenStudy (anonymous):
did u solve by inequalities
OpenStudy (anonymous):
i did this step
x^-4x>12
x^2+4-4>12-4
x>8
OpenStudy (john_es):
What happens to x of -4x?
OpenStudy (anonymous):
x^2-4x>12
OpenStudy (john_es):
I mean, I think it should be something like,
\[x^2-4x-12>0\]
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OpenStudy (anonymous):
yes
OpenStudy (john_es):
Then you have to factorize this polinomy.
OpenStudy (anonymous):
no
OpenStudy (anonymous):
it dont have
OpenStudy (john_es):
Well, the right solution should be, I think, in this way,
\[(x+2)(x-6)>0\]And find the regions where x satisfies this inequality. As far as I know, I think the solution should be like this,
\[(-\infty,-2)\cup(6,+\infty)\]
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