Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (anonymous):

x2-4x>12 (-6)(+2) is this correct

OpenStudy (anonymous):

wait, what? whats the full equation?

OpenStudy (loser66):

you have to have the form of solution are x<-6 or x>2

OpenStudy (anonymous):

x2-4x>12

OpenStudy (anonymous):

x^2-4x>12 u mean?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sorry having problems with my computer..lol

OpenStudy (anonymous):

never mind

OpenStudy (anonymous):

x<-2 or x>6

OpenStudy (john_es):

I think the solution should be an interval.

OpenStudy (john_es):

An open interval to be more specific.

OpenStudy (anonymous):

did u solve by inequalities

OpenStudy (anonymous):

i did this step x^-4x>12 x^2+4-4>12-4 x>8

OpenStudy (john_es):

What happens to x of -4x?

OpenStudy (anonymous):

x^2-4x>12

OpenStudy (john_es):

I mean, I think it should be something like, \[x^2-4x-12>0\]

OpenStudy (anonymous):

yes

OpenStudy (john_es):

Then you have to factorize this polinomy.

OpenStudy (anonymous):

no

OpenStudy (anonymous):

it dont have

OpenStudy (john_es):

Well, the right solution should be, I think, in this way, \[(x+2)(x-6)>0\]And find the regions where x satisfies this inequality. As far as I know, I think the solution should be like this, \[(-\infty,-2)\cup(6,+\infty)\]

OpenStudy (john_es):

The graph method is ok as well.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!