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Mathematics 20 Online
OpenStudy (anonymous):

Help me out with this question?

OpenStudy (anonymous):

OpenStudy (anonymous):

So i multiply the y by 4 right?

hartnn (hartnn):

cam you isolate y from first equation ? hint subtract 2x from both sides...

OpenStudy (anonymous):

Ohh...

hartnn (hartnn):

multiplying by 4 , will become the method of elimination :)

OpenStudy (anonymous):

so i got y=-1 and x- 4y=11

OpenStudy (anonymous):

opps i mean -11

hartnn (hartnn):

y=-1 ?? how ? 2x+y=-11 so y = -11-2x got this ?

OpenStudy (anonymous):

okay and the other equation is -4y=11-2x

hartnn (hartnn):

i never asked to isolate y from other equation :P but oh, well, you can plug in the y, from 1st equation into other! plug in y=-11-2x in 2nd equation what u get ?

OpenStudy (anonymous):

how the frick do i plug in that huge equation into the other one

hartnn (hartnn):

lol, quite easy, if you try :) \(\huge y=-11-2x \:\: in \quad 3x-4y =11 \\ \implies \huge 3x-4(-11-2x)=11 \) got this ?

OpenStudy (anonymous):

ok but there is an x in that parenthesis how ughhh im so dumb i hate math :(

hartnn (hartnn):

the term -4(-11-2x) is making you feel dumb ?? lets make this term feel dumb instead :P distribute -4 to each(both) term! like a(b+c) = ab+ac ry ?

hartnn (hartnn):

*try

OpenStudy (anonymous):

ok i got 3x + 44 + 8x =11

hartnn (hartnn):

see! how simple it was :D you are absolutely correct :) now find 'x' from that... 3x+8x = ... ?

OpenStudy (anonymous):

i did 11x + 44 =11 -44 on each side so x =33

OpenStudy (anonymous):

i mean -33

OpenStudy (anonymous):

that isn't even one of the answers :S

hartnn (hartnn):

11x +44 =11 so, 11x = -33 so, x = ... ?

hartnn (hartnn):

-33 is 11x, not x :P

hartnn (hartnn):

divide both sides by 11

OpenStudy (anonymous):

- 3 !!!!!

hartnn (hartnn):

correct! :D

OpenStudy (anonymous):

so which equation do i plug -3 in for

hartnn (hartnn):

ideally, we need not find the 'y' but just make sure the 'y' you get is correct put x=-3 in any equation y=-11-2x

hartnn (hartnn):

y=-11-2(-3) = ... ?

OpenStudy (anonymous):

-5 :D

hartnn (hartnn):

you got it ;)

OpenStudy (anonymous):

help me out with one more??

hartnn (hartnn):

only one?

hartnn (hartnn):

as many as you need :)

OpenStudy (anonymous):

You're a sweetheart :D

OpenStudy (anonymous):

hartnn (hartnn):

oh, am i ?? i thought the same thing bout u :

hartnn (hartnn):

multiply first equation by -3 what uget ?

hartnn (hartnn):

you know why i am multiplying 1st equation by -3 ?

OpenStudy (anonymous):

yes so it can equal 9 :D

OpenStudy (anonymous):

-9x - 6y = -36

hartnn (hartnn):

ok, you multiplied by 3, right ? even that will do :) now add both the equations :)

OpenStudy (anonymous):

is it -27

hartnn (hartnn):

what is -27 ?

OpenStudy (anonymous):

no wait -45

hartnn (hartnn):

add these 2 equations -9x - 6y = -36 9x +6y=-9

OpenStudy (anonymous):

dont the 9x and 6y cancel out and that's left with -45

hartnn (hartnn):

-45 is correct right side! whats on the left side ?

OpenStudy (anonymous):

i thought they cancel out

OpenStudy (anonymous):

or is it 18x + 12y =-45

hartnn (hartnn):

yeah, and what remains ? like whats 9x-9x = ... ?

OpenStudy (anonymous):

x ??

hartnn (hartnn):

its NOT 18x + 12y

hartnn (hartnn):

ok, whats 9-9 = ... ?

OpenStudy (anonymous):

0 !

hartnn (hartnn):

yes so 9x-9x = 0

hartnn (hartnn):

left side = 0 0 =-45

hartnn (hartnn):

is that even possible ?

OpenStudy (anonymous):

no so its no solutions right??

hartnn (hartnn):

absolutely :)

OpenStudy (anonymous):

thanks, what about this one :)

OpenStudy (anonymous):

do i add or subtract x?

hartnn (hartnn):

just add the 2 equation...

OpenStudy (anonymous):

0 = 0 so that means infinite right? :)

hartnn (hartnn):

oh, you are so smart! :D

hartnn (hartnn):

correct :)

OpenStudy (anonymous):

says you i bet you're in like a super smart math that i dont even know about

hartnn (hartnn):

my field of study is not math, its electronics, but we study one subject of math each year, not too high level though :) i won't consider myself super smart :P

OpenStudy (anonymous):

Oh i see. So do you make electronics or fix them and stuff?

hartnn (hartnn):

nopes, not fix them, just understand how they work

OpenStudy (anonymous):

oh i see :) can you help me out with this last one?

hartnn (hartnn):

sure

OpenStudy (anonymous):

thanks lovely

hartnn (hartnn):

know the method of elimination ?

OpenStudy (anonymous):

kind of

hartnn (hartnn):

do u know that in elimination method, we try to make the co-efficient of any one variable, same in both equations......

hartnn (hartnn):

so. lets start, multiply 1st equation by 5 what u get ?

hartnn (hartnn):

and ask me if you don't know "why" i am doing so

OpenStudy (anonymous):

its bc you need the x's to be the same so first one is 10x+30y=60 and second equation is 10x - 25y=50

hartnn (hartnn):

-12 * 5 = -60 in the 1st equation what did u do with the 2nd one???

OpenStudy (anonymous):

wai tis the second one 10 * 5 =50

hartnn (hartnn):

10x+30y=-60 right ? now you had to multiply 2nd equation by "2" to make that 10x....

hartnn (hartnn):

not by 5

OpenStudy (anonymous):

oh so 10 * 2 = 20

hartnn (hartnn):

yeah, tell me what u get entire 2nd equation?

OpenStudy (anonymous):

10x + 2y = 20

hartnn (hartnn):

2y ??? -5y*2 = -10y , isn't it ?

OpenStudy (anonymous):

IDK LOL so wait the second equation is -5y * 2 = -10y

OpenStudy (anonymous):

how can there be two y's

hartnn (hartnn):

no i meant, 5x-5y=10 multiplying this by 2, we get 10x-10y =20 got this ?

OpenStudy (anonymous):

oohhh now i get it

hartnn (hartnn):

cool :) so, 10x+30y=-60 10x-10y =20 just subtract the 2nd equation from 1st eqation! and note that 'x' gets eliminated :)

OpenStudy (anonymous):

:( i got -60 im doing something wrong

hartnn (hartnn):

-60 for what ?

OpenStudy (anonymous):

x

hartnn (hartnn):

but the 'x' gets cancelled 1x-10x = 0

hartnn (hartnn):

****10x-10x=0

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