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Mathematics 21 Online
OpenStudy (lifeisadangerousgame):

Help with understanding this as well?

OpenStudy (lifeisadangerousgame):

OpenStudy (lifeisadangerousgame):

Based on what my book says, I need to do this: f(x) = x^3 y = x^3 x = y^3 but I don't know how to go from there

OpenStudy (lifeisadangerousgame):

Anyone? :/

OpenStudy (lifeisadangerousgame):

@mxdd17 Can you help?

OpenStudy (anonymous):

Looked over it, but I can't remember how to do it. Last semester I probably could.

OpenStudy (lifeisadangerousgame):

aww okay

OpenStudy (anonymous):

I think you need to solve for y.

OpenStudy (lifeisadangerousgame):

then its\[y = \sqrt[3]{x}\]

OpenStudy (anonymous):

Domain and range would be All real numbers

OpenStudy (lifeisadangerousgame):

Can you show me? I don't really understand this

OpenStudy (anonymous):

You found the inverse (x = y^3) The next step would be to isolate x, y=3√x If x was in a square root, you would eliminate the negative numbers from the domain so that there would not be any imaginary numbers but it's a cube root, so it is unaffected by them. This means that there are no restrictions. To find the range, you isolate the x variable to get x=y^3. There are no restrictions for this either, so the range and domain are ALL REAL NUMBERS

OpenStudy (lifeisadangerousgame):

Does that mean it is a function?

OpenStudy (anonymous):

the domain and range are a range of numbers \[(-\infty,\infty)\]

OpenStudy (lifeisadangerousgame):

Okay:D THank you!

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