A force F = 2xî + 2ĵ + 3z(square)k is acting on a particle. Find the work done by this force in displacing the body from (1, 2, 3) m to (3, 6, 1) m

option a -10J
option b 100 J
option c 10 J
option d 1J

Question

A force F = 2xî + 2ĵ + 3z(square)k is acting on a particle. Find the work done by this force in displacing the body from (1, 2, 3) m to (3, 6, 1) m 

option a -10J
option b 100 J
option c 10 J
option d 1J

anonymous · Answer

$$W=\int\limits_{r1}^{r2} F*dr$$

dr=dxi + dyj + dzk

anonymous · Answer

huh?

plainntall · Answer

It is the definition of work.  You find the cross product of the force vector and the change in position vector.

anonymous · Answer

i want the answer not explanation

anonymous · Answer

$$W=\int\limits_{1}^{3} 2xdx + \int\limits_{2}^{6} 2dy + \int\limits_{3}^{1} 3z ^{2}dz$$  

work is a scaler product between F and dr

plainntall · Answer

My mistake dot product not cross product.