Question

how do i rearange this to be boiling point?

ln(1.501)=−(40.7/8.03145)(1/x−1/373.15)

Answer 1

\(ln(1.501)=-\dfrac{40.7}{8.03145}*(\dfrac{1}{x}-\dfrac{1}{373.15})\)

\(ln(1.501)*(-\dfrac{8.03145}{40.7})=\dfrac{1}{x}-\dfrac{1}{373.15}\)

\(ln(1.501)*(-\dfrac{8.03145}{40.7})+\dfrac{1}{373.15}=(\dfrac{1}{x})\)

\(x=\dfrac{1}{(ln(1.501)*(-\dfrac{8.03145}{40.7})+\dfrac{1}{373.15})}\)

Answer 2

dude you are so awesome

Answer 3

glad i could help