Find all solutions to the equation. 7 sin^2x - 14 sin x + 2 = -5
pi/2?
ok how do i solve this question?
add 7 to both sides of the equation so you have \[7\sin^2(x) - 14\sin(x) + 7 = 0\] divide each term by 7 \[\sin^2(x) -2\sin(x) + 1 = 0\] this is a quadratic equation the factorises to a perfect square hope this helps
ok thank you guys
oops should have been add 5
Wait you're both giving me two different equations i'm confused.
the correct equation occurs by adding 5 to both sides of the equation \[7\sin^2(x) - 14\sin(x) + 7 = 0\]
No confusion now. I getting out while the getting is good. Sorry about that.
ok so once i have 7sin2(x)−14sin(x)+7=0 can you help me factor it please because the sin throws me off a bit
ok... divide each term by 7
to make it easy let u = sin(x) so you have \[u^2 - 2u + 1 = 0\] can you factor this... its a perfect square
(u-1)(u-1)?
yep... or (u -1)^2 = 0 reverse the substitution (sin(x) -1)^2 = 0 so you need to solve sin(x) -1 = 0 hope that makes sense
ok i understand the factoring now. so i would get sinx=1?
you will... to you need to find \[x = \sin^{-1}(1)\]
Wait im confused how did you get x=sin^-1(1)
its the arcsin.... or what angle gives sin a value of 1. its 90 degrees or pi/2
oh ok
thank you for your help:)
hope it makes sense
its a bit easier now thank you
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