Question

Help with this math problem?
Find 3 consecutive odd integers with a sum of 63

Answer 1

Ok so in this problem we have 3 different integers that have to equal 63. Also they are 3 odd numbers. So for the first number we'll call it "x" . Now for the second number since it's odd we'll make it "x+2" Since x, will be odd we have to add it by another 2 to keep it odd and to make it consecutive. (odd #'s in a row) The third consecutive odd integer will be "x+4". Now we have:
x+ (x+2)+(x+4)=63 [Add all like terms on left side of equal sign together]
3x+6=63= [Subtract 6 on both sides]
3x=57 [Divide both sides by 3]
x=19.
This means our first term of "x" is 19. Now for the 2nd term we have to do
x+2, don't forget that "x" is 19, so we do : 19+2=21 for our 2nd term. Now for our last term we have to do "x+4" and 19+4=23. That means our three consecutive odd integers are 19,21,23. If u add them all up to double-check it u'll see it does in fact equal 63 :P So for a future problem u have 2:
-Take a look at the word problem to see what it's saying (three consecutive odd integers equalling 63)
-Place variables for the integers we don't know yet but r trying 2 find (x, x+2, x+4)
-Find x (19)
-Plug it back in for the actual terms :P x=19, x+2=19+2=21, & x+4=10+4=23)

Did that help a bit 4 u 2 understand? :)

Answer 2

Yes, thank you so much :D

Answer 3

Np :P if u need any more help just ask and I"ll try 2 do my best :p sry it took so long tho lol stupid delete key on my keyboard stopped working -.- oh well :3

Answer 4

Lol it's okay :D and thank you again.

Answer 5

np :)