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Mathematics 15 Online
OpenStudy (anonymous):

someone help me with derivatives

OpenStudy (anonymous):

for the following function , find the derivative and evaluate at x=2 , -4, 0 and pi

OpenStudy (anonymous):

where is the function ??

OpenStudy (anonymous):

Y=2x

OpenStudy (anonymous):

f(x)=2x f'(x)=2

OpenStudy (anonymous):

the derivative is linear so you cannot substitute values in

OpenStudy (anonymous):

unless it is asking you to evaluate the original function

OpenStudy (anonymous):

ok thanks so then the answer is y'=2

OpenStudy (anonymous):

how do i evaluate it at x=2, -4, 0, pi

OpenStudy (anonymous):

that just means substituting the x-values into the function but f'(x)=2 does NOT have any x-values included since its linear (therefore, a straight line on the graph)

OpenStudy (anonymous):

so that does mean that every number for example y'(-4) = 2

OpenStudy (anonymous):

basically, for the derivative for every x-value, the y-value stays as 2

OpenStudy (anonymous):

so if you were to graph it it would just be |dw:1379903863259:dw|

OpenStudy (anonymous):

and the original f(x) [function] looks like |dw:1379903953692:dw|

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