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OpenStudy (anonymous):
for the following function , find the derivative and evaluate at x=2 , -4, 0 and pi
OpenStudy (anonymous):
where is the function ??
OpenStudy (anonymous):
Y=2x
OpenStudy (anonymous):
f(x)=2x
f'(x)=2
OpenStudy (anonymous):
the derivative is linear
so you cannot substitute values in
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OpenStudy (anonymous):
unless it is asking you to evaluate the original function
OpenStudy (anonymous):
ok thanks so then the answer is y'=2
OpenStudy (anonymous):
how do i evaluate it at x=2, -4, 0, pi
OpenStudy (anonymous):
that just means substituting the x-values into the function
but f'(x)=2 does NOT have any x-values included since its linear (therefore, a straight line on the graph)
OpenStudy (anonymous):
so that does mean that every number for example y'(-4) = 2
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OpenStudy (anonymous):
basically, for the derivative
for every x-value, the y-value stays as 2
OpenStudy (anonymous):
so if you were to graph it it would just be |dw:1379903863259:dw|
OpenStudy (anonymous):
and the original f(x) [function] looks like |dw:1379903953692:dw|