Question

Find the derivative of the function.
y = (e^(7u) − e^(−7u)/(e^(7u) + e^(−7u))

Answer 1

how did you get that?

Answer 2

don't you see the form of sinh (7u)/cosh(7u)??

Answer 3

I thought that the quotient rule would be used.

Answer 4

you have the formula of \(sinh x = \dfrac{e^x -e^{-x}}{2}\) and \(cosh x = \dfrac{e^x+e^{-x}}{2}\) yours is 7u, not x . and combine them, you have sinh (7u)/ cosh (7u) = tanh (7u)
derivative of tanh(7u)= sech (7u)
that's it

Answer 5

nope?? don't agree with me?? hehehe.. if you want to apply quotient rule, ok, go ahead.