Question

Please help

A linear equation has an x-intercept of (5,0) and a y-intercept of (0,-8). Determine the slope of the line and write the equation in standard form. 


A.m = -8/5 ; 8x - 5y = 40


B.m = -8/5 ; 8x + 5y = 40


C.m = 8/5 ; 8x + 5y = 40


D.m = 8/5 ; 8x - 5y = 40

Answer 1

Hello,

do you know the first step?

Answer 2

not at all @Compassionate

Answer 3

>A linear equation has an x-intercept of (5,0) and a y-intercept of (0,-8). Determine the slope of the line and write the equation in standard form. 

We know its asking for a linear equation .
we know x(5, 0) & y(0, -8)

Our first challenge is:

>Determine the slope

Okay, the slope formula is: \[m = \frac{ y _{2}-y_{1} }{ x_{2} -x_{1} }\]

Where: \[y_{2} = -8 \rightarrow y_{1} = 0\]

So, we know that y2 = -8 and y1 = 0

Can you guess what x2 and x1 are?

Answer 4

5 and 0 @Compassionate

Answer 5

actually, x2 = 0 and x1 = 5

Is this making sense so far? Good. Okay, now take the points and plug them into the slope equation. \[m= \frac{ y2 - y1}{ x2 - x1 }\]

Answer 6

If you're having trouble let me know.

Answer 7

I got 8/5

Answer 8

\[m = \frac{ -8 - 0 }{ 0 - 5 } = \frac{ -8 }{ -5 } = \frac{ 8 }{ 5 }\]

Okay, so we just did the first part of the equation by finding the slope.

> and write the equation in standard form. 


Okay, so, basically, when you have two points and a slope, you can use the point-slope formula.

\[y - y_{1} = m(x - x_{1})\]


We also know our points are [(5, 0), (0, -8)]

Where y1 = 0
Where x1 = 5
m = 8/5

So now, just plug all that into the point-slope equation, and solve.

Answer 9

ok so the answer would be C. @Compassionate

Answer 10

Correct.

Answer 11

@Compassionate thank you