During a head on collision between two automobiles, the occupants are decelerated rapidly. Use the idea of work to explain why a air bag that quickly inflates in front of an occupant reduces the likelihood of injury.
Work is a change in energy, I think. To stop the occupant, there is a set amount of work to be done to take away all of that occupant's kinetic energy. That work is \(W=F\cdot d\approx F\ d\) Work, \(W\), will be the same no matter what. So, if the distance along which the stopping force acts (\(d\)) is greater, because it is traveled through as the occupant goes into the airbag, then the force (\(F\)) must be lesser. If you hit your head on something hard, you the force \(F\) is in a short distance \(d\), and so, with that constant \(W\), the \(F\) must be greater.
Any questions?
no i dont think so! thank you! :)
You're welcome!
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