Question

Help!

Answer 1

Let \(\LARGE f(x)=x^2+x g'(1)+g''(2)\) and \(\LARGE g(x)=f(1).x^2+xf'(x)+f''(x)\).
Then

Answer 2

f'(1)+f'(2)=0
g'(2)=g'(1)
g''(2)+f''(3)=6
None of these

Answer 3

I don't think the normal way of doing it will work,its a never ending loop seems to me

Answer 4

whats f'' (x) =... ?

Answer 5

from f(x)

Answer 6

if i do it that way its just a loophole

Answer 7

f''(x)=2 maybe

Answer 8

it is

Answer 9

no sorry,f''(1)= 2

Answer 10

f''(x)=constant=2

Answer 11

actually

Answer 12

f'' (x) is also=2
yeah

Answer 13

um so..

Answer 14

so f'''(x)+f''''(x) all are equal to 0 right

Answer 15

right

Answer 16

so f'(x)= 2x+g'(1)
and g'(1)=2f(1)+f'(1)+f''(1)+f'''(1)
g'(1)=2(1+g'(1)+g''(2))+ 2 + g'(1) + 2 + 0..
it keeps getting complicated lol

Answer 17

i know it can be done this way but not even sure if this method will yield the answer also its too lengthy,can we have an alternate method?

Answer 18

BURN IT AND BURY IT IN THE BACKYARD xD

Answer 19

should work^^

Answer 20

this question is very interesting...
i tried to solve it for like an hour but i still did not get the any answer,
did you guys already know what's the answer?? pls. inform me..thanks!