Question

A grain silo is shown below.

What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22/7 for pi.

a. 13,750 ft3
b. 14,012 ft3
c. 262 ft3
d. 4,583 ft3

Answer 1

The silo is in a form of cylinder. And the volume of grain that will completely fill this is the same as the volume of the cylinder itself. Just be reminded of the V = pir^2h where pi = 22/7 r = 5 and h = 175

Answer 2

use the volume of a cylinder formula \[V=pir ^{2}h\]
and then add half the volume of the sphere at the top
\[V=(4/3)(\pi)r ^{3}\]
don't forget to divide the volume of the sphere by 2 !

Answer 3

I really don't know what a silo is. I thought that is just a handle but anyway @jonnymiller thanks for informing. Therefore, after finding the volume of the cylinder. Add half-volume of the spherical top of the silo.
It is like \[V = \frac{ 4 }{ 3 } \pi r^3\] leading to\[V = \frac{ }{ 3 } \pi r^3\]

Answer 4

\[V = \frac{ 2 }{ 3 } \pi r^3\]

Answer 5

V = pi*r^2*h + (1/2)*(4/3)*pi*5^3

V = 22/7 * 25 * 175 + (2/3)* 22/7 * 125

V = ? @lowcard2

Answer 6

Silo

b. 14,012 ft3

Answer 7

That is what I am thinking.

Answer 8

correct

Answer 9

I actually got 14006.26 cubic feet