Question

find the reminder when f(x)=-2x^3+3x^3-x+1/2 is divided by 2x+1

Answer 1

It's all bout remainder theorem. Do you know something about it?

Answer 2

r u sure it is 3x^3??

Answer 3

ot it is 3x^2?

Answer 4

oopzz.....sorry itz 3x^2...

Answer 5

@prasheelasingh , something about remainder theorem. Remember?

Answer 6

is the remainder 2?

Answer 7

maybe for some sort of reference, read this one http://www.purplemath.com/modules/remaindr.htm

Answer 8

have u ever practiced dis type of division?

Answer 9

itz quite difficult for me...

Answer 10

Anyway, to solve this we must solve variable x by our (divisor I think: just take a look at 2x+1)
2x+1 = 0
Therefore, x = -1/2
After that, substitute the value we got into the polynomial equation (take a look at -2x^3+3x^2-x+1/2)
Hence,
\[-2(\frac{ -1 }{ 2 })^3 + 3(\frac{ -1 }{ 2 })^2 - \frac{ -1 }{ 2 } + \frac{ 1 }{ 2 }\]
Then,
\[-2(\frac{ -1 }{ 8 }) + 3(\frac{ 1 }{ 4 }) + 1\]
\[\frac{ 1 }{ 4 }+\frac{ 3 }{ 4 }+1\]
Therefore, the remainder is 2.

Answer 11

The way I used is based from remainder theorem.

Answer 12

i have tried it by.....evaluating -1/2 in the equation......... -2(-1/2)^3+3(-1/2)^2-(-1/2)+1/2=1.5

Answer 13

opppzzz.......
i got it.....

Answer 14

May be just do some sort of rechecking. Or you can post your solution so we can both verify.

Answer 15

finally............thanks....i was wrong......

Answer 16

the reminder is = to 2.......

Answer 17

No problem. :))