Relative velocity, Last problem Pls HELP !!!
@atlas
This is a very simple and largely a geometrical question. You need to find out how much distance on the x-axis has particles a and b moved w.r.t each other in time 't'. Similarly you need to find out how much distance apart they have moved in y-axis in time 't'
Since you have to give your answers in terms of theta and omega........... use omeaga = theta/t (constant angular velocity)
x component of a = \(L \cos \theta \)
for b also x component wud be same ?
x-component of Vab wud be 0 then is it
|dw:1379936271400:dw|
yeah you are right............x component of v-ab would always be 0
You can see that for yourself - the two particles will never move along the x-axis at any point of time 't'
\[\bar r_A=Lcos(\theta) \hat i+Lsin(\theta) \hat j\]\[\bar r_B=Lcos(\theta) \hat i-Lsin(\theta) \hat j\]Position of particle A versus particle B is\[\bar r=\bar r_A-\bar r_B=2L\sin(\theta) \hat j\]\[\bar v_{ab}=\frac{ d \bar r }{ dt }=2Lcos(\theta)\frac{ d \theta }{ dt }\hat j=2Lcos(\theta) \omega \hat j\]
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