The combustion of propane may be described as"
C3H8 (g)+5O2(g)-- 3CO2(g)+4H2O(g)

How many grams of O2 are needed to completely burn 36.2g of C2H8?
G/O2

Question

The combustion of propane may be described as"
C3H8 (g)+5O2(g)--> 3CO2(g)+4H2O(g)

How many grams of O2 are needed to completely burn 36.2g of C2H8?
G/O2

aaronq · Answer

find the amount of moles 36.2 g of C2H8 are.

Use the stoichiometric coefficients to build a ratio, like this:

e.g. for a general reaction:

                      $\color{red}{a}A + \color{blue}{b}B$ $\rightleftharpoons$ $ \color{green}{c}C$

where upper case are the species (A,B,C), and lower case (a,b,c) are the coefficients (in red),

                     $\dfrac{n_A}{\color{red}{a}}=\dfrac{n_B}{\color{blue}{b}}=\dfrac{n_C}{\color{green}{c}}$

from here, you can solve for moles then convert to grams.

To convert mass to moles, use the relationship:

                             $n=\dfrac{m}{M}$

        where, M=molar mass, m=mass, and n= moles.

anonymous · Answer

I don't quite  understand the second part

aaronq · Answer

post what you've done and i'll help you correct it