Question

4. A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground.
a. Find the velocity of the object when it is 30.0 m above the ground.
b. Find the total distance the object travels during the fall.

Answer 1

tell me about the equations that comes in your mind ?

Answer 2

\[S = u t + \frac{ 1 }{ 2 } a t ^{2}\]

Answer 3

try to complete it now

Answer 4

\[v^{2}-v_{o}^{2}=2gh\]

Answer 5

ok i will try

Answer 6

i can't do it !!!

Answer 7

see equation
vo=0,then.............

Answer 8

s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]

Answer 9

for part ii)
v = u + at
v = at
because u = 0 since the object is being released
and v is the speed calculated above
t = v/a

Answer 10

s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \]