How do I prove that, for example \[e^\pi > \pi^e\]
if you take the natural log of both sides you can get something that should be easier to solve
Well it's not that I want to "solve it", since it's just real numbers. I want to give a proof for why the above statement is true. And to secure the integrity of the proof, of course I cannot use what I want to proof as an assumption, as that would simply lead me to believe it is true in any case, even if it should be wrong.
ahh ok then I'd generalize it do \(e^n>n^e\) and test for n=e, n>e, and n<e
then compare graphs maybe, or start with something that is trivially true and flow into this
Not sure, for my classes I was allowed a direct pf on this one
I'd love to start off with something trivially true and "flow" into this. In such a case, though, my problem is that I don't know what that trival part would be.
idk I'll think on it gtg to class
You can try a serial expansion (McLaurin series) of both sides as if they were functions, until first order. Then compare.
Better look here, http://answers.yahoo.com/question/index?qid=20110103144014AAaEFMk
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