If f(x) = 2+{6}/{x}+{5}/{x^{2}}, find f'( x ). Find f'( 3 ). Find f''( x ). Find f''( 3 ).
\[f(x) = 2+{6}/{x}+{5}/{x^{2}}, \]
Ok well first you need to take the derivative. Do you know how to do that?
yes
Alright so have you worked that out yet?
\[f \left( x \right)=2+6x ^{-1}+5x ^{-2}\] \[\frac{ d }{ dx }\left( x \right)^{n}=nx ^{n-1}\]
i know how to get f'(x) and f'(3), but idk about f''(x) and f''(3)
That second ' is just telling you to take the second derivative of the function. So if you have the first derivative worked out just take the derivative of whatever that is. I got -6-10x by the way, did you find the same thing?
\[\frac{ d }{dx }f'\left( x \right)=f''\left( x \right) and so on.\]
oh oops lol its (-6/x^2)-(10/x^3)
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