Please Help!!! A stone is released from a balloon that is descending at a constant speed of 10 m/s. Neglecting air resistance, after 20 s the speed of the stone is:
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OpenStudy (anonymous):
gravity constant is 10 m/s^2 ?
OpenStudy (anonymous):
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OpenStudy (anonymous):
after 1 second, 0 speed, 19 s after that 19*10 = 190 m/s
(no air resistance)
OpenStudy (anonymous):
The answer should be 206
OpenStudy (anonymous):
I used the formula v= v(initial) + at
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OpenStudy (anonymous):
dont forget the direction
OpenStudy (anonymous):
For kinetic problems, I believe you take direction into consideration for acceleration, but what about velockty?
OpenStudy (anonymous):
the speed is initially 10 m/s upwards
OpenStudy (anonymous):
so it takes 1 second to "lose" that speed
OpenStudy (anonymous):
then it starts accelerating downwards for 19 seconds
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OpenStudy (anonymous):
my problem was that i put -10 instead of 10
OpenStudy (anonymous):
why is velocity positive if it's going down
OpenStudy (anonymous):
either way is right
OpenStudy (anonymous):
if it's a negative, you get 196
OpenStudy (anonymous):
that's an answer choice as well
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OpenStudy (anonymous):
a = 9.81 ?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
then it's right, i assumed 10.0
OpenStudy (anonymous):
19 second at 9.81 m/s^2
OpenStudy (anonymous):
the right answer is 206. you see my dilemma?
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