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Mathematics 18 Online
OpenStudy (anonymous):

Please Help!!! A stone is released from a balloon that is descending at a constant speed of 10 m/s. Neglecting air resistance, after 20 s the speed of the stone is:

OpenStudy (anonymous):

gravity constant is 10 m/s^2 ?

OpenStudy (anonymous):

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OpenStudy (anonymous):

after 1 second, 0 speed, 19 s after that 19*10 = 190 m/s (no air resistance)

OpenStudy (anonymous):

The answer should be 206

OpenStudy (anonymous):

I used the formula v= v(initial) + at

OpenStudy (anonymous):

dont forget the direction

OpenStudy (anonymous):

For kinetic problems, I believe you take direction into consideration for acceleration, but what about velockty?

OpenStudy (anonymous):

the speed is initially 10 m/s upwards

OpenStudy (anonymous):

so it takes 1 second to "lose" that speed

OpenStudy (anonymous):

then it starts accelerating downwards for 19 seconds

OpenStudy (anonymous):

my problem was that i put -10 instead of 10

OpenStudy (anonymous):

why is velocity positive if it's going down

OpenStudy (anonymous):

either way is right

OpenStudy (anonymous):

if it's a negative, you get 196

OpenStudy (anonymous):

that's an answer choice as well

OpenStudy (anonymous):

a = 9.81 ?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

then it's right, i assumed 10.0

OpenStudy (anonymous):

19 second at 9.81 m/s^2

OpenStudy (anonymous):

the right answer is 206. you see my dilemma?

OpenStudy (anonymous):

Yeah i see, but it's wrong :)

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