The cost to produce a product is modeled by the function f(x) = 5x^2 − 70x + 258 where x is the number of products produced. Complete the square to determine the minimum cost of producing this product.
A. 5(x − 7)^2 + 13; The minimum cost to produce the product is $13.
B. 5(x − 7)^2 + 13; The minimum cost to produce the product is $7.
C. 5(x − 7)^2 + 258; The minimum cost to produce the product is $7.
D. 5(x − 7)^2 + 258; The minimum cost to produce the product is $258.
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
how far did you get?
OpenStudy (anonymous):
This was my first question like this
jimthompson5910 (jim_thompson5910):
what is the axis of symmetry in this case?
OpenStudy (anonymous):
5(x-7)^2
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jimthompson5910 (jim_thompson5910):
hint: the axis of symmetry of ax^2 + bx + c is x = -b/(2a)
jimthompson5910 (jim_thompson5910):
what is the axis of symmetry of 5x^2 − 70x + 258
OpenStudy (anonymous):
5?
jimthompson5910 (jim_thompson5910):
what are 'a' and 'b' in this case?
OpenStudy (anonymous):
5 and 70
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jimthompson5910 (jim_thompson5910):
close
a = 5
b =-70
jimthompson5910 (jim_thompson5910):
now plug those into x = -b/(2a)
OpenStudy (anonymous):
Negative 700?
OpenStudy (anonymous):
i dont think thats right
jimthompson5910 (jim_thompson5910):
x = -b/(2a)
x = -(-70)/(2*5)
x = ???
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OpenStudy (anonymous):
-70?
jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
-7?
jimthompson5910 (jim_thompson5910):
try again
OpenStudy (anonymous):
negative 70 divided by ten no?
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OpenStudy (anonymous):
postive 7?
jimthompson5910 (jim_thompson5910):
yes it's positive 7
jimthompson5910 (jim_thompson5910):
so h = 7
jimthompson5910 (jim_thompson5910):
now that we know x = 7, plug it into the equation and tell me what you get
OpenStudy (anonymous):
608?
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jimthompson5910 (jim_thompson5910):
that's way too high
OpenStudy (anonymous):
5(7)^2 − 70(7) + 258 <--- plug it in like that right?
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
giving you what?
OpenStudy (anonymous):
is it anywhere in the hundreds?
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OpenStudy (anonymous):
you said 608 is high
jimthompson5910 (jim_thompson5910):
yeah 608 is way too high
OpenStudy (anonymous):
so if it was 300 or 400 it'd still be too high?
jimthompson5910 (jim_thompson5910):
yes, it's a 2 digit number
OpenStudy (anonymous):
13?
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jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
so that's why the equation turns into
f(x) = 5(x-7)^2 + 13
OpenStudy (anonymous):
Thank you, thanks alot
jimthompson5910 (jim_thompson5910):
np
OpenStudy (anonymous):
thats wrong
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