Question

Solve the equation.
2(x-2)^2 +x^2 = x(x+50)-48x

Answer 1

I thought it was no solution, but the answer is apparently that the solution set is 1 and 4, but I don't see how

Answer 2

You want the answer or steps?

Answer 3

The steps

Answer 4

\[2(x-2)^2 + x^2 = x(x+50) - 48x\]
\[2( x^2 -4x +4) + x^2 = x^2 + 50x - 48x\]

Answer 5

get that?

Answer 6

Not really. Why did you rewrite them that way?

Answer 7

cause i have to, (x-2)^2 = (x-2)(x-2) and that makes the x^2 - 4x + 4

Answer 8

Oh right

Answer 9

and x(x + 50) = x*x + x*50 = x^2 + 50x

Answer 10

right

Answer 11

\[2x^2 -8x +8 + x^2 = x^2 +2x\]
\[3x^2 - 8x + 8 -x^2 -2x=0\]

Answer 12

how bout that?

Answer 13

\[2x^2 -10x +8=0\]
\[2(x^2-5x+4)=0\]

Answer 14

Alright, yeah, I got that part with the left side

Answer 15

2(x-4)(x-1)=0
x = 4 OR x = 1

Answer 16

Oh alright. Thanks. There wasn't anything of the sort in my notes but I remember doing something like it in class.

Answer 17

ghe, enjoy :)