Question

Please help & Explain!
fg-9h=1oj (Solve for g)

Answer 1

your first step is to move that "-9h" term over

you do this by adding 9h to both sides (since addition undoes subtraction)

to get

\[\large fg-9h=1oj\]


\[\large fg-9h+9h=1oj+9h\]


\[\large fg+0h=1oj+9h\]


\[\large fg+0=1oj+9h\]


\[\large fg=1oj+9h\]

Answer 2

what's your next step?

Answer 3

wait im confused in step 3 where di you get "0" from?

Answer 4

-9h + 9h = 0h

since

-9 + 9 = 0

Answer 5

and because they add to 0, the "9h" terms go away on the left side (which is what we want)

does that make sense

Answer 6

ok i get that now. i dont no what to do next

Answer 7

fg means "f times g"

Answer 8

what is the opposite of multiplication?

Answer 9

division

Answer 10

so that means you divide both sides by f to isolate g

\[\large fg=1oj+9h\]

\[\large \frac{fg}{f}=\frac{1oj+9h}{f}\]

\[\large \frac{1g}{1}=\frac{1oj+9h}{f}\]

\[\large 1g = \frac{1oj+9h}{f}\]

\[\large g = \frac{1oj+9h}{f}\]

Answer 11

hopefully all that makes sense