What is the length of the altitude drawn to the hypotenuse?
well the problem needs ratios of corresponding sides in similar triangles.
|dw:1379971312978:dw| I thin u mean the length of AB
Am I right ...?
Yes, the length of AB.
Here's how to do this one, consider the triangle ADC and ABC angle A = angle B = 90 degree angle C is common angle D = angle CAB (remaining angle) there for triangle ADC and ABC r similar (AAA) consider the triangle ADC and ABD angle A = angle ABD = 90 degree angle D is common angle C = angle BAD (remaining angle) there for triangle ADC and ABC r similar (AAA) so tri. ADC = tri. ABC tri. ADC = tri. ABD therefor tri.ABC = tri.ABD considering the 2 triangle ABC and ABD 11/AB = AB/13 Corresponding sides of congruent triangle) Now solve it and u could find the length of AB hope this will help ya!
use the fact that \[\cot(90 - \alpha) = \tan(\alpha) \] therefore the ratios are \[\frac{13}{AB} = \frac{AB}{11}\] so \[AB^2 = 143\]
Awesome! thanks so much everyone :)
u r welcome
but you need to similarty proof, by Angle Angle Postulate
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