Graph the system of equations x + y = 7 2x - 4y = 8 My graphing calculator doesn't make any sense, how do I solve this without it?
Solve both of those equations for y. Objective: Put into y=mx+b form.
y = -x + 7 y = -.5x - 2
I'm not sure about your second equation. I think you should have a positive slope.
y=-x+7 y=x/2-2 Now graph using the y-intercepts and the slopes of each equation. y=mx+b (0,b) is the y-intercept m is the slope
what exactly am i even supposed to be finding though? the x and y intercepts of each line?
Well you said you wanted to solve the system of equations, right? So you are looking for when the lines meet. At what point, do they meet?
(6, 1)
Yep. That works. You can always check yourself by pluggin' in your result into both equations to see if both equations hold. Like so: (x=6,y=1) y=-x+7 1=-6+7 1=1 (1=1 is a true statement so (6,1) works for this equation but what about the other) y=x/2-2 1=6/2-2 1=3-2 1=1 (again this is a true statement) Since both of our equations hold, that means we have found the correct solution.
i have another one that i'm trying to figure out too. this one says to solve it algebraically (with substitution or elimination) 5x + y = 9 6x + 10y = 2
if i do it with substitution i get this 5x + y = 9 solved for y is y = -5x + 9 6x + 10(-5x + 9) = 2 6x - 50x + 9 = 2 6x - 50x = -7 -44x = -7 x = .159 which doesnt seem right at all, but if i try it with elimination then i get this 5x + y = 9 6x + 10y = 2 -10(5x + y = 9) = -50x - 10y = -90 -50x - 10y = -90 + 6x + 10y = 2 ---------------------- -44x = -88 x = 2 which seems right so, if x = 2, then the equations now look like this 10 + y = 9, and 12 + 10y = 2 y = -1 and 10y = -10, or y = -1
well 10(9)=90
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