Question

Differntiate A=A(1/2)^5

Answer 1

\[A(1/2)^5\]

Answer 2

\[\huge A= A_o \left( \frac{ 1 }{2 } \right) ^ {t/20} \] i think you need to differentiate from here. Then plug in your t value.

Answer 3

Ohhhh I c

Answer 4

ill try that

Answer 5

0.1617....

Answer 6

for Ao you can plug in the (Ao/32) since there's only 1/32 remaining.

Answer 7

Is it 5(1/2)^99/20

Answer 8

How'd you get that? That's not the derivative.

Answer 9

well I took the exponent and put it in front
and subtracted 1 form the exponent

Answer 10

isnt that the rule?

Answer 11

No... you don't have a simple power function. you have one of these exponential a^x functions http://tutorial.math.lamar.edu/Classes/CalcI/DiffExpLogFcns_files/eq0031MP.gif

Answer 12

A((1/2)^t/20)(ln)(1/2)

Answer 13

\[A((t/20)^{t/20}\ln(1/2) \]

Answer 14

0.0224.....

Answer 15

I got an answer much smaller than that

Answer 16

It's not quite as simple as just doing the rule with a^x

Answer 17

i think im just gonna save this question for my math friend

Answer 18

thx anyways

Answer 19

Well the answer should be \[\Large \frac{ dA }{ dt } = -3.38 \times 10 ^{-5} A_o\] but it takes a bit of work to get to.