Question

Evaluate the derivative of the function below at the point (6, 0.035). Round to four decimal places.
f(x) = 5/(x**2-4 x)**2

Answer 1

I put it in the exponent form,
\[f(x)=5(x^2-4x)^{-2}\]Then, use chain rule,
\[f'(x)=5\cdot2\cdot(x^2-4x)^{-3}\cdot(2x-4)=\frac{20x-40}{(x^2-4x)^3}\]
Then substitue the x=6,
\[f'(6)=0.0463\]

Answer 2

thanks!!!!!!

Answer 3

You're welcome.