Link 1 helps answers the 2nd link Medal will be awarded if your answer is correct/accurate and if you explained it, because our teacher really sucks at teaching.
@mathstudent55
thank you, but I am not on that I am number 5 from link 2 and link 1 helps answers that
I think point J is (0,6) and point M is (7, 1.3), but I am not for sure for point M
I am sorry for the first one, A (-12, 0) B (0,4) --> slope AB = \(\dfrac{4-0}{0-(-12)}=\dfrac{1}{3}\) you are right
X(-12,5.5) T(-1,9)--> slope XT= \(dfrac{9-5.5}{-1-(-12)}= \dfrac{7}{22}\)
@Loser66 Quit checking number 2, I am on #5 of the 2nd link
WG you are right but should say it's =3, not 3/1
3 over 1 is the same as 3
#4 correct
you didn't do 7,8,9,10 yet, how to check?
I don't know them checked, I need to know how to do them
What is JM as points, but I need to know what M is; I got (7, 1.3), but I need the exact number though
Maybe @Compassionate can help.
@jim_thompson5910
@mathstudent55 I need your help
we make mistake at WG It must be -3 not 3. and pay attention at the segments,
|dw:1379991374780:dw|
|dw:1379991401104:dw|
the value of slopes equal, it means the segments parallel
those for problem #3
okay my answer is changed on my paper, but not on the scanned thing
you have to have #3 done and base on it, do #5
you see NR//JM --> slopes are the same, no need to calculate JM since you don't have the integer there, just calculate NR whose coordinates are integers. does it make sense?
for equation of the line JM, you have slope of it, (=slope of NR, let say it is m) and point J (0,6) just plug them into the formula y = mx +b to find b, and then plug back to find formula of the line. got what I mean?
what numbers do I have to work with
Are you making number up?
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