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Medal will be given if shown work and final answer. Determine whether the integral converges or diverges, and if it converges find its value.
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\[\int\limits_{4}^{\infty}\frac{ 1 }{ x \sqrt{x} }dx\]
yes ut converges to one
Could someone please explain how they got their answer?
@Hero
@jim_thompson5910 could you help me?
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\[\int\limits_{4}^{\infty}\frac{ dx }{ x \sqrt{x} }=\int\limits_{4}^{\infty}x^{-\frac{ 3 }{ 2 }}\,dx=\left[ -2x^{-\frac{ 1 }{ 2 }} \right]_{4}^{\infty}=\lim_{x \rightarrow \infty}-2x^{-\frac{ 1 }{ 2 }} -\left( -2(4)^{-\frac{ 1 }{ 2 }}\right)\]
Thank you so much!
does that make sense?
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