Question

simplify 3/4-squareroot of 13 leave your answer in surd form

Answer 1

\[3/4-sqrt{13}\]

Answer 2

its already simplified?

Answer 3

no.....itz not........

Answer 4

ok i got -1.1488

Answer 5

wait

Answer 6

i mean -2.8556

Answer 7

ummmm answer should be in surd form.....

Answer 8

surd form?

Answer 9

yeah......u know surds?

Answer 10

wht type of math class?

Answer 11

well surds is an irrational root of a rational number..........m in year 12........

Answer 12

um would it be this?

Answer 13

as in answer or equation?

Answer 14

answer

Answer 15

how did u get the answer?

Answer 16

is it correct, or potentially correct? answer that first lol

Answer 17

no....i dont think so.........

Answer 18

does surd form look like that?

Answer 19

ummm yes...

Answer 20

i got it from calculator

Answer 21

i didnt know that the calculator could simplify that equation.....

Answer 22

Are you sure it's (3/4) - 13^.5?

Answer 23

i was told this calculator can convert into surd form http://www.wolframalpha.com/

Answer 24

Because I'm not sure how you're simplifying 13^.5.... 13 is prime

Answer 25

ummm thatz is what am tryin to simplify.....itz quite hard....

Answer 26

i simplfief for u and got decim,al

Answer 27

the 13

Answer 28

surds are anothe name for radicals... so the answer needs to be written usign radicals.

Answer 29

So is the idea we have to combine the terms somehow?

Answer 30

campbell

Answer 31

is this right?

Answer 32

just a quick question about the expression is it

1. \[\frac{3}{4 - \sqrt{13}}\]

or

2. \[\frac{3}{4} - \sqrt{13}\]

Answer 33

the first one....

Answer 34

wow u should of told me

Answer 35

This is why I said "Are you sure it's (3/4) - 13^.5?" lol. I need to learn to Tex on this thing,

Answer 36

ok... so you need to rationalise the denominator

multiply by 1.... in another form so its

and use the difference of 2 squares

this will give a rational denominator

\[\frac{3}{4 - \sqrt{13}} \times \frac{4 + \sqrt{13}}{4 + \sqrt{13}}\]

Answer 37

do you think you can work it out from here @prasheelasingh

Answer 38

ummm yea....thanks

Answer 39

glad to help

Answer 40

ummm i need help.......

Answer 41

so do the denominator 1st

its the difference of 2 squares

\[(a - b)(a + b)=a^2 - b^2\]

you need


\[a = 4 ... and... b = \sqrt{13}\]

Answer 42

ummm i got 16 -13.... ????????????

Answer 43

correct... so thats means the denominator is 3

now is there a common factor in the numerator that cancels..?

Answer 44

hmmmm is the answer