Question

Help please

Answer 1

Graph the function. Identify the vertex and axis of symmetry.\[f(x)=-2x ^{2}+2x-1\]

Answer 2

A.

axis of symmetry: x = -0.5
vertex: (–0.5, –0.5)

B.

axis of symmetry: x = 0.5
vertex: (0.5, –0.5)

C.

axis of symmetry: x = 0.5
vertex: (0.5, 0.5)

D.

axis of symmetry: x = 0.5
vertex: (0.5, 0.5)

Answer 3

@amistre64 @ganeshie8

Answer 4

Do you know how to find the vertex of a parabola?

Answer 5

I remember you that when you have a parabola in the form,
\[y=ax^2+bx+c\]
one of the forms that let you obtain the parabola is first, to calculate the x coordinate of the vertex,
\[x_v=\frac{-b}{2a}\] Then, plug this value into the equation,
\[y_v=ax_v^2+bx_v+c\]
And you'll obtain the y coordinate of the vertex of the parabola.

Answer 6

the equation give us clues to narrow down the options;

the leading term defines a family of graphs all with the same basic shape, and its sign (+/-) tell us a direction.

Can you narrow it down ?

Answer 7

Is it B

Answer 8

B or D, hard to tell by the pics tho

Answer 9

make sure you didnt copy B onto D for me

Answer 10

@amistre64 B is axis of symmetry: x = 0.5
vertex: (0.5, –0.5)
and D is axis of symmetry: x = 0.5
vertex: (0.5, 0.5)
But the graph is the same

Answer 11

they have different vertex

Answer 12

the y vertex part is negative, so id say B is good

Answer 13

are you sure @amistre64

Answer 14

im never sure ;)

Answer 15

B is good. The pics are a little confusing but the numbers are Ok.

Answer 16

thanks @amistre64 @John_ES

Answer 17

You're welcome. If you have more problems of this type I recommend you to try the formulas I wrote before, although I think you probably know them.