f(x)=1/(x^2+1)
g(x)=2x^2-x+4
Evaluate:
f(g(x) )=(f∘g)(x)

Question

f(x)=1/(x^2+1)
g(x)=2x^2-x+4
Evaluate:
f(g(x) )=(f∘g)(x)

anonymous · Answer

When you see the expression f(g(x)), the g(x) is inside f's ( ), right?
So...think of it as putting g(x) inside the f(x) function.

anonymous · Answer

How do you put g(x) inside f(x) = 1/(x^2 + 2) ?
You simply replace that x that is in the denominator of the function with g(x)...that is, you replace the x with 2x^2-x+4

anonymous · Answer

f(x) = 1/(x^2+1)...................that's given.
Now write f(x) replacing the x with 2x^2-x+4
f(g(x)) = 1/((2x^2-x-4)^2+1)

anonymous · Answer

Hello..............are you there?

anonymous · Answer

Sorry about that had to return to work. Thanks for all the help. When i working on this problem i was having trouble with how it should look being that f(x) is a rational.