Question

I really need help, please!
I am having the worst time with these problems.
I can't remember how to do them and I have been trying to work on this work sheet for quite a while now, which is putting me behind in my class.
I could really use some help! I just need someone to explain how to solve it and then I think I can get the rest. I have 11 problems on my work sheet. I have posted the question below. Thank you! :)

Answer 1

Sure !
But say that please !:)

Answer 2

where is the question ?

Answer 3

It's right there. It took a minute to upload. And E.ali, say what? lol
Thanks guys! :)

Answer 4

1. your two points are (-5,5) and (1,-2)
do you agree ?

Answer 5

I'd say so, yes.

Answer 6

K !
To find the distance between two point we use this formula :
\[\sqrt{(x1-x2)^2+(y1-y2)^2}\]

Answer 7

Fisrt find the place of the points and write them please :)

Answer 8

@Madds96

Answer 9

the square root of (x2 - x1)^2 + (y2 - y1)^2
(-5,5) x1 = -5 and y1 = 5
(1,-2) x2 = 1 and y2 = -2

lets plug it into the formula
square root of (1 - 5)^2 + (-2 - 5)^2
square root of (-4)^2 + (-7)^2
square root of 16 + 49
square root of 65 = 8.06 rounded to 8.1

Answer 10

do the same thing for the second problem

Answer 11

I'm honestly really confused still...lol
I'm sorry. I'm awful at math... :(

Answer 12

square roots and powers can be confusing.

Answer 13

the points on the second graph are what ?

Answer 14

CAn you find the Coordinate ?

Answer 15

(-5, 1), (4, 0) I believe. :)

Answer 16

correct..
lets put them in the formula
(-5,1) x1 = -5 and y1 = 1
(4,0) x2 = 4 and y2 = 0

sq rt (x2 - x1)^2 + (y2 - y1)^2
sq rt (4 -(-5)^2 + (0 - 1)^2

can you finish ?

Answer 17

Is this one sq rt (x2 - x1)^2 + (y2 - y1)^2 1.41?

Answer 18

sq rt (4 + 5)^2 + (0 - 1)^2
sq rt 9^2 + -1^2
sq rt 81 + 1
sq rt 82 = 9.05 rounds to 9.1

do you understand how I got this ?

Answer 19

sq rt (x2 - x1)^2 + (y2 - y1)^2 is the distance formula

Answer 20

I understand how you got this part; sq rt (4 + 5)^2 + (0 - 1)^2
sq rt 9^2 + -1^2
sq rt 81 + 1
sq rt 82 = 9.05 rounds to 9.1
But I don't understand how you got that out of this part; (-5,1) x1 = -5 and y1 = 1
(4,0) x2 = 4 and y2 = 0

sq rt (x2 - x1)^2 + (y2 - y1)^2
sq rt (4 -(-5)^2 + (0 - 1)^2

Answer 21

First find your points. Then you have to label your points.
(x1, y1) and (x2,y2)

you still with me ?

Answer 22

your points are (-5,1) -- this is x1 and y1
(4,0) -- this is x2 and y2
understand ?

Answer 23

I think so. so it would be: (x[-5], y[1]), (x[4], y[0])?

Answer 24

yes...you have 2 sets of points.
First set contains x1 and y1 and 2nd set contains x2 and y2

Answer 25

Ok. I understand that part. :)

Answer 26

(-5,1) can either be set 1 or set 2, it doesn't matter. Just be sure and label each point correctly

Answer 27

Ok. I'll make it be set 1, since it comes first I'll be able to understand it better.

Answer 28

whatever makes it easier for you

Answer 29

do you have any more questions ?

Answer 30

Ok, for (-5, 1) would it be written like this; (-5, 1) * 1 = -5?

Answer 31

no....where did that come from ?

Answer 32

why are you multiplying it by 1 ?

Answer 33

Oh wait, I read one of the things above wrong... :P

Answer 34

do you understand about labeling the points and subbing it into the formula ?

Answer 35

if not, this may help
http://www.mathwarehouse.com/algebra/distance_formula/index.php

Answer 36

good luck :)

Answer 37

I'm not sure. This is and example that my teacher gave me of how I have to write it out. (-6, -10), (-2, -10)

d = \[\sqrt{(x2 - x1)^2 + (y2 - y1)^2}\]
\[\sqrt{(-2 - -6)^2 + (-10 - -10)^2}\]
\[\sqrt{(-2 + 6)^2 + (-10 + 10)^2}\]
\[\sqrt{4^2 + 0^2}\]
\[\sqrt{16 = 4}\]

Answer 38

Realyyyyyyyyyyyyyyyy right !:)

Answer 39

The problem is, it all looks like gibberish to me.

Answer 40

that is correct

Answer 41

WAIT!!! I think I might have it!

Answer 42

Would a graph with the plots (5, -5), (1, -2) be started like this?:

\[\sqrt{(1 - 5)^2 + (-2 - -5)^2}\]\[\sqrt{(1 + 5) ^2 + (-2 + -5)^2}\]

Answer 43

\[\sqrt{(6)^2 + (-7)^2}\]

Answer 44

not quite
sq rt (1 - 5)^2 + (-2 - (-5)^2
sq rt (1 - 5)^2 + (-2 + 5)^2
sq rt -4^2 + 3^2

Answer 45

Oh, so if its 2 negatives, you change the subtraction to addition, but if its 2 positive's, you leave the subtraction?

Answer 46

do not distribute anything through the parenthesis

Answer 47

if it is 2 negatives multiplied together, change it to a positive. If it is 2 positives, you do not change anything

Answer 48

so yes.....you leave the subtraction

Answer 49

So would the final answer to the above problem be: sq rt 16 + 9

Answer 50

yes

Answer 51

Ok. I'm pretty sure that I get how to do it now. Can we do another one to be sure?

Answer 52

of course

Answer 53

Ok, lets do #2. I believe that the points are (-5, 1), (0, 4)

Answer 54

(-5,1) and (4,0)

Answer 55

sq rt (0 - -5)^2 + (4 - 1)^2, right?

Answer 56

wait...your right (4,0)

Answer 57

correct

Answer 58

wait......mistake......check your points.............it is (4,0)

Answer 59

Oh my bad... so sq rt (4 - -5) + (0 - 1)?

Answer 60

yes....sorry about that

Answer 61

It's not your fault, it's mine. :)

Answer 62

So then, (4- -5)^2 + (0 - 1)^2?

Answer 63

yes

Answer 64

sq rt 81 + 1?

Answer 65

yes

Answer 66

And its done now?

Answer 67

no.....sq rt 82 = 9.05 which rounded to the nearest tenths = 9.1

Answer 68

Opps, I forgot about that step... So to do it, I add the 81 & 1 = 82. Then find the sq rt. 9.05, round to 9.1?

Answer 69

this helps...
http://www.math.com/students/calculators/source/square-root.htm

Answer 70

do not find the square root of 9.05.....that is the answer, but you have to round the answer to the tenths place, which is 9.1

Answer 71

find the square root of 82

Answer 72

Thats what I meant in my head, I typed it wrong. :P

Answer 73

no problem.....if I had a dollar for every mistake I made, I would be rich

Answer 74

Haha so would I! :) Thank you for all of the help, I really appriciate it!

Answer 75

no problem...thats what I am here for

Answer 76

have a good day

Answer 77

Thanks, you too!