Question

WILL BE GIVING MEDALS FOR RIGHT ANSWER! PLEASE!
Which function below is the inverse of f(x) = x^2 - 6?
A: x^2/16
B: +-4sqrtx
C:+-sqrtx+16
1/x^2-16

Answer 1

Do you know how to find the inverse of a function?

Answer 2

Not one with a exponent. @mathstudent55

Answer 3

@thomaster

Answer 4

The important thing is to know the method.
Here is the method, then we'll go over the problem step by step.

1. Write y instead of f(x)
2. Switch x and y.
3. Solve for y.
4. Replace y with \(f^{-1}(x) \)

Answer 5

Well, if you have f(x)= x^2 - 6
you would switch them to y=x^2 -6
x=y^2 -6 and solve for y.
so x+6= y^2
To cancel the square you would squareroot each side.
so the \[\sqrt{x+6} = y\]

Answer 6

So the problem would look like this X = y^2 - 6? Thank you @AJBB I need to know how to do this problem also though. Like really thoroughly.

Answer 7

That isn't even one of the answers either. @AJBB

Answer 8

\( f(x) = x^2 - 6 \)

1. \( y = x^2 - 6 \)

2. \( x = y^2 - 6 \)

3.

\( x = y^2 - 6 \)

\(x + 6 = y^2\)

\(y^2 = x + 6\)

\(y = \pm \sqrt{x + 6} \)

4. \(f^{-1}(x) = \pm \sqrt{x + 6} \)