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OpenStudy (anonymous):
the midpoint of uv is (5 -11) the coordinates of one endpoint are u 3,5 find the coordinates of endpoint v
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OpenStudy (anonymous):
The midpoint is \[
\frac{u+v}{2}=m
\]
OpenStudy (anonymous):
We know \(m=(5,-11)\)
OpenStudy (anonymous):
and \(u=(3,5)\)
OpenStudy (anonymous):
Let \(v=(v_1,v_2)\)
OpenStudy (anonymous):
\[
\frac{3+v_1}{2}=5\\
\frac{5+v_2}{2}=-11
\]
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OpenStudy (anonymous):
@spada get it?
OpenStudy (anonymous):
so it that the answer
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
No, you need to solve for \(v_1\) and \(v_2\).
OpenStudy (anonymous):
The answer is \(v=(v_1,v_2)\)
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OpenStudy (anonymous):
still confused?
OpenStudy (anonymous):
You don't know how to solve an equation?
OpenStudy (anonymous):
\(\color{blue}{\text{Originally Posted by}}\) @wio
\[
\frac{3+v_1}{2}=5\\
\frac{5+v_2}{2}=-11
\]
\(\color{blue}{\text{End of Quote}}\)
OpenStudy (anonymous):
what is v1 and v2
OpenStudy (anonymous):
You don't know how to solve for \(v_1\) in the first equation?
Is that what you are telling me?
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OpenStudy (anonymous):
No one taught you how to isolate a variable, but they expect you to find midpoints? Is that what I'm hearing?
OpenStudy (anonymous):
yes just what is the answer to the problem?
OpenStudy (anonymous):
No dice.
OpenStudy (anonymous):
?
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