HELP PLEASE !! Medal will be rewarded !

Question

anonymous · Answer

attachment

ganeshie8 · Answer

plugin the numbers into the given equation ?

ganeshie8 · Answer

$\large \sqrt{x-y} + m = d$

ganeshie8 · Answer

y is last two digits of ur birth year (u may fake if u want ;) )
m is month
d is day

anonymous · Answer

Okay

ganeshie8 · Answer

wat do u get for the equation ?

anonymous · Answer

Let me work it out

ganeshie8 · Answer

okie

anonymous · Answer

I can't get the answer .. I don't know how to work this out ! :(

ganeshie8 · Answer

if u can show me wat do u have... maybe i can help :)

ganeshie8 · Answer

did u plugin the values in equation ?

anonymous · Answer

I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?

ganeshie8 · Answer

nope, have u read the question ?
it wants u to put ur date of birth in the given equation, and solve x

ganeshie8 · Answer

$\large \sqrt{x-y} + m = d$
            ^

anonymous · Answer

Okay

ganeshie8 · Answer

put the year u born in that place

ganeshie8 · Answer

which year ?

anonymous · Answer

Don't I use the values given in the question ?

anonymous · Answer

Ohhh nevermind , I just read the question wrong . My bad

ganeshie8 · Answer

No, those values are for ur great great grandpa Nikola Tesla.... 
they're not urs lol

ganeshie8 · Answer

cool :)

anonymous · Answer

Okay so I was born in 96

ganeshie8 · Answer

$\large \sqrt{x-96} + m = d$
                         ^

ganeshie8 · Answer

there it goes !
wat about month and date

ganeshie8 · Answer

i feel like im interviewing u lol

anonymous · Answer

Haha month is 4 and day is 22

ganeshie8 · Answer

thanks for giving it one shot :)

ganeshie8 · Answer

$\large \sqrt{x-96} + 4 = 22$

anonymous · Answer

Alright so now what to do :o

ganeshie8 · Answer

solve for x

ganeshie8 · Answer

start by subtracting 4 both sides

anonymous · Answer

Okay

ganeshie8 · Answer

$\large \sqrt{x-96} + 4 = 22$

subtract 4 both sides

$\large \sqrt{x-96}  = 18$

anonymous · Answer

18

ganeshie8 · Answer

Yes ! next, square both sides

anonymous · Answer

You mean square 96 and 18 ?? :o

ganeshie8 · Answer

$\large \sqrt{x-96} + 4 = 22$

subtract 4 both sides

$\large \sqrt{x-96}  = 18$

square both sides

$\large (\sqrt{x-96})^2  = (18)^2$

ganeshie8 · Answer

like this..

ganeshie8 · Answer

since u r not happy wid radical, we're killing it by squaring both sides !

ganeshie8 · Answer

$\large \sqrt{x-96} + 4 = 22$

subtract 4 both sides

$\large \sqrt{x-96}  = 18$

square both sides

$\large (\sqrt{x-96})^2  = (18)^2$

$\large x-96  = 324$

anonymous · Answer

Oh okay !

ganeshie8 · Answer

wats our next step ?

anonymous · Answer

Add 96 to both sides ?

ganeshie8 · Answer

thats it !

anonymous · Answer

Okay so that would be 420 ? (;

ganeshie8 · Answer

Yes ! good job !!

anonymous · Answer

Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o

ganeshie8 · Answer

oh, it asks to check if the solution is extraneous or now.

ganeshie8 · Answer

*not

anonymous · Answer

Yeah , I don't know what that means .

ganeshie8 · Answer

its very easy to check,

simply put the solution u got for x in the original (ur bday ) equaiton

anonymous · Answer

Alright

ganeshie8 · Answer

ur bday equation :-

$\large \sqrt{x-96} + 4 = 22$

put x  = 420 here, 
IF this satisfies this equation, then its NOT an extraneous solution.

anonymous · Answer

I worked it out and I got 420=324 :o

ganeshie8 · Answer

careful, check again

anonymous · Answer

But that's not true , so does that mean the solution IS extraneous ?

anonymous · Answer

Oh okay ..

ganeshie8 · Answer

i want u check again,

ganeshie8 · Answer

Checking if x=420 is extraneous solution or not :-

$\large \sqrt{x-96} + 4 = 22$

put x = 420

$\large \sqrt{420-96} + 4 = 22$

anonymous · Answer

Right

ganeshie8 · Answer

Checking if x=420 is extraneous solution or not :-

$\large \sqrt{x-96} + 4 = 22$

put x = 420

$\large \sqrt{420-96} + 4 = 22$

$\large \sqrt{324} + 4 = 22$

ganeshie8 · Answer

Checking if x=420 is extraneous solution or not :-

$\large \sqrt{x-96} + 4 = 22$

put x = 420

$\large \sqrt{420-96} + 4 = 22$

$\large \sqrt{324} + 4 = 22$

$\large 18 + 4 = 22$

anonymous · Answer

Ohhhh okay ! That makes more sense !

anonymous · Answer

THANK YOU

ganeshie8 · Answer

Checking if x=420 is extraneous solution or not :-

$\large \sqrt{x-96} + 4 = 22$

put x = 420

$\large \sqrt{420-96} + 4 = 22$

$\large \sqrt{324} + 4 = 22$

$\large 18 + 4 = 22$

$\large 22 = 22$

TRUE, so x=420 is NOT an extraneous solution.

ganeshie8 · Answer

np :) yw !